Explicit and implicit functions
All functions discussed so far have been
explicit functions, defined in terms of 1 variable only, such as in the form of \(y=f(x)\).
Implicit functions are defined in terms of more than 1 variable, such as in the form of \(f(x,y) = 0 \).
Implicit differentiation
- Terms involving \(x\) only are differentiated normally with respect to \(x\).
- Terms involving \(y\) only are differentiated with respect to \(y\), multiplied by \(\dfrac{dy}{dx} \).
- Terms involving products of \(x\) and \(y\) are differentiated using the rules above and the product rule.
The resulting equation is rearranged to make \(\dfrac{dy}{dx} \) the subject.
Equations of tangents and normals
Once the gradient function \(\dfrac{dy}{dx} \) is found, the equation of the tangent or normal at any specific point on the curve can be found in the
usual way.
Turning points
Turning points can be found in the usual way, by solving \(\dfrac{dy}{dx} = 0 \).
Depending on the gradient function, the solution to the equation \(\dfrac{dy}{dx} = 0 \) might be in the form \(y=f(x)\) or \(x=f(y)\).
In that case, substituting \(x\) or \(y\) in the original equation and solving will provide the \(x\)- or \(y\)-coordinate of the turning point(s).
Implicit differentiation
- Terms involving \(x\) only are differentiated normally with respect to \(x\).
- Terms involving \(y\) only are differentiated with respect to \(y\), multiplied by \(\dfrac{dy}{dx} \).
- Terms involving products of \(x\) and \(y\) are differentiated using the rules above and the product rule.
The resulting equation is rearranged to make \(\dfrac{dy}{dx} \) the subject.
3