Acceleration in a straight line (#126)

Acceleration in a straight line (#126)

bEquations of motion/b

(\text{average velocity} = \dfrac{\text{displacement}}{\text{time}})

(\text{acceleration} = \dfrac{\text{final velocity}-\text{initial velocity}}{\text{time}})

For the movement of an object in a straight line with constant acceleration, the following letters are used:

(s) for displacement
(u) for initial velocity
(v) for final velocity
(a) for acceleration
(t) for time

These are used for the so-called isuvat/i formulae:

(v = u + at)

(s = ut + \frac{1}{2}at2)

(s = \frac{1}{2}(u+v)t)

(v2 = u^2 + 2as)

(s = vt - \frac{1}{2}at2)

To use these formulae, write down the known variables from the question. The question will tell you at least 3 variables out of the 5. Identify the appropriate equation to use for solving the unknown variables.

bVertical motion under gravity/b

isuvat/i formulae can also be used to model vertical motion under gravity.

For a falling object, acceleration towards the Earth is constant (ignoring air resistance) and is equal to the gravitational constant (g) ((\approx 9.81ms-1)).

For an object being thrown upwards vertically, it will have a negative acceleration equal to (-g) (again ignoring air resistance).

[b]uFormulae for constant acceleration for motion in a straight line[/u]/b

(v = u + at)

(s = ut + \frac{1}{2}at2)

(s = \frac{1}{2}(u+v)t)

(v2 = u^2 + 2as)

(s = vt - \frac{1}{2}at2)