Be able to differentiate composite functions using the chain rule.y=f(u)y=f(u)y=f(u), u=g(x)u=g(x)u=g(x),dydx=dydu×dudx\dfrac{dy}{dx} = \dfrac{dy}{du} × \dfrac{du}{dx} dxdy=dudy×dxduOr {f[g(x)]}′=f′[g(x)]g′(x)\big\{f\big[g(x)\big]\big\}' = f'\big[g(x)\big]g'(x) {f[g(x)]}′=f′[g(x)]g′(x)
