GCSE Physics AQA 8463

Distance and displacement

Distance is how far an object moves. Distance does not involve direction. Distance is a scalar quantity.

Displacement includes both the distance an object moves, measured in a straight line from the start point to the finish point and the direction of that straight line. Displacement is a vector quantity.

Students should be able to express a displacement in terms of both the magnitude and direction.

Speed

Speed does not involve direction. Speed is a scalar quantity.

The speed of a moving object is rarely constant. When people walk, run or travel in a car their speed is constantly changing.

The speed at which a person can walk, run or cycle depends on many factors including: age, terrain, fitness and distance travelled.

Typical values may be taken as: walking ̴ 1.5 m/s running ̴ 3 m/s cycling ̴ 6 m/s.

Students should be able to recall typical values of speed for a person walking, running and cycling as well as the typical values of speed for different types of transportation systems.

It is not only moving objects that have varying speed. The speed of sound and the speed of the wind also vary.

A typical value for the speed of sound in air is 330 m/s. hrStudents should be able to make measurements of distance and time and then calculate speeds of objects.

For an object moving at constant speed the distance travelled in a specific time can be calculated using the equation:

$\text{distance travelled} = \text{speed} × \text{time}$

$s = v t$

distance, s, in metres, m speed, v, in metres per second, m/s time, t, in seconds, s hrStudents should be able to calculate average speed for non-uniform motion.

Velocity

The velocity of an object is its speed in a given direction. Velocity is a vector quantity.

Students should be able to explain the vector–scalar distinction as it applies to displacement, distance, velocity and speed.

Students should be able to explain qualitatively, with examples, that motion in a circle involves constant speed but changing velocity.

The distance-time relationship

If an object moves along a straight line, the distance travelled can be represented by a distance-time graph.

The speed of an object can be calculated from the gradient of its distance-time graph.

If an object is accelerating, its speed at any particular time can be determined by drawing a tangent and measuring the gradient of the distance-time graph at that time.

Students should be able to draw distance-time graphs from measurements and extract and interpret lines and slopes of distance-time graphs, translating information between graphical and numerical form.

Students should be able to determine speed from a distance-time graph.

Acceleration

The average acceleration of an object can be calculated using the equation:

$\text{acceleration} = \dfrac{\text{change in velocity}}{\text{timetaken}}$

$a = \dfrac{\Delta v}{t}$

acceleration, a, in metres per second squared, m/s2 change in velocity, ∆v, in metres per second, m/s time, t, in seconds, s

An object that slows down is decelerating.

Students should be able to estimate the magnitude of everyday accelerations. hrThe acceleration of an object can be calculated from the gradient of a velocity-time graph.

The distance travelled by an object (or displacement of an object) can be calculated from the area under a velocity–time graph.hrStudents should be able to:

• draw velocity-time graphs from measurements and interpret lines and slopes to determine acceleration **- interpret enclosed areas in velocity–time graphs to determine distance travelled (or displacement)
• measure, when appropriate, the area under a velocity-time graph by counting squares.** hrThe following equation applies to uniform acceleration:

$(\text{final velocity})^2 - (\text{initial velocity})^2 = 2 × \text{acceleration} × \text{distance}$

$v^2 - u^2 = 2as$

final velocity, v, in metres per second, m/s initial velocity, u, in metres per second, m/s acceleration, a, in metres per second squared, m/s2 distance, s, in metres, m

Near the Earth’s surface any object falling freely under gravity has an acceleration of about 9.8 m/s². hrAn object falling through a fluid initially accelerates due to the force of gravity. Eventually the resultant force will be zero and the object will move at its terminal velocity.

Students should be able to:

• draw and interpret velocity-time graphs for objects that reach terminal velocity
• interpret the changing motion in terms of the forces acting.