A-Level Physics OCR A H556

5.1.4: Ideal gases

#5.1.4a

amount of substance in moles; Avogadro constant NA equals 6.02 × 1023 mol–1

#5.1.4b

model of kinetic theory of gases

*Assumptions for the model:

  • large number of molecules in random, rapid motion
  • particles (atoms or molecules) occupy negligible volume compared to the volume of gas
  • all collisions are perfectly elastic and the time of the collisions is negligible compared to the time between collisions
  • negligible forces between particles except during collision*
#5.1.4c

pressure in terms of this model

#5.1.4d

(i) the equation of state of an ideal gas pV=nRTpV = nRT, where n is the number of moles

(ii) techniques and procedures used to investigate PV=constantPV = \text{constant} (Boyle’s law) and PT=constant\dfrac{P}{T} = \text{constant}

PAG8

(iii) an estimation of absolute zero using variation of gas temperature with pressure

PAG8

#5.1.4e

the equation pV=13Nmcˉ2pV = \dfrac{1}{3} Nm\bar{c}^2 ,

where N is the number of particles (atoms or molecules) and cˉ2\bar{c}^2 is the mean square speed

Derivation of this equation is not required.

#5.1.4f

root mean square (r.m.s.) speed; mean square speed

Learners should know about the general characteristics of the Maxwell-Boltzmann distribution.

#5.1.4g

the Boltzmann constant; k=RNAk = \dfrac{R}{N_A}

#5.1.4h

pV=NkTpV = NkT ; 12mcˉ2=32kT\dfrac{1}{2}m\bar{c}^2= \dfrac{3}{2}kT

Learners will also be expected to know the derivation of the equation 12mcˉ2=32kT\dfrac{1}{2}m\bar{c}^2= \dfrac{3}{2}kT from pV=13Nmcˉ2pV = \dfrac{1}{3} Nm\bar{c}^2 and pV=NkTpV = NkT

#5.1.4i

internal energy of an ideal gas.

5.1.3
Thermal properties of materials
5.2.1
Kinematics of circular motion